The pressure and thermal characteristics are both particularly important when using CO2 for PVC based cannons. We don't want to over pressurize our PVC and we also don't want to freeze down the PVC while filling the chamber.

The over pressurization, which you may have noticed as "sometimes my gun shoots hot" is of particular concern with PVC. Your marker "shoots hot" when some liquid gets past the regulator and then turns to gas. This is also of particular concern when a CO2 tank and it's regulator are installed horizontally on a cannon - more opportunities for liquid flow.

So let's take a peak at The Science of CO2 and then relate that to markers, tanks, cannons, and cannon design.

is from WarPig and is cached here. The WarPig article has a good discussion of CO2 and it's attributes relative to Paintball. I highly suggest you read the WarPig article. For safety's sake please pay particular attention to the critical temperature and pressure of CO2. The critical temperature and pressures are critical for safe designs and we'll address them in these discussions on this page an on this site. While I'm at it, a good site for conversions is http://www.Convert-Me.com.

Although CO2 is not an ideal gas, for most of these discussions, we can get pretty close if we (1) follow the Ideal Gas Law equations, (2) use known values for CO2, and (3) check to make sure we're starting and ending where we want in the phase chart. Staying in a safe zone essentially means ensuring we will always have gas (primarily as that means we don't have liquid available to make even more gas available - we've only got temperature vs pressure scaling)..

The ideal gas law can be stated as P*V = (m/MW)*R*T

For CO2:

P = pressure in atmospheres, where 1 atm = 14.7 PSI at sea levelNow, to simplify for STP (standard temperature & pressure)

V = volume of gas in liters, where 1L = 61.02 in3

m = mass in grams of CO2

MW = molecular weight of CO2; MW = 12+32=44

R = 0.082 liter*atm/K

T = temperature in kelvins [which is 298 K at 25 C or 77 F]

(1atm)*(1L) = (mg/44)*(0.082)*(298tk)So, to simplify for "paintball normal conditions" for CO2, we assume 77F, CO2, pressure in PSI, and volume in cubic inches and yield:

or1.8 grams CO2 == 1 Liter volume at 1 atmpsphere pressure (sea level) at 298 kelvin temperature (77F)

1.8 grams CO2 = 61.02in3In general, and for our purposes, this equation holds as long as the pressure is below the vapor pressure for any temperature we're interested in. And this is the primary check we're interested in for our computational tests and design rules checks as if we're under the vapor pressure we know we're dealing with gas.

For some quick examples consider a 12 gr CO2 cyclinder. How much liquid and how much gas is inside? It's actually a tough question as for a fixed temperature we'll maintain pressure as the volume increases up until the liquid is gone. So it's suicidal to say "the 12 gram is at 1200 PSI so if I make a chamber 3 times as big I'll have gas at 400 PSI and that's safely at the upper limit of my Whistle Valve". And that would be incorrect and perhaps hazardously so. All we know is that there is supposed to be 12 grams of CO2 inside.

For cannons, we typically want to know:

## Volume of CO2 at a given pressure for a given amount

This is commonly asked "how big of a chamber do I need for 150 PSI PVC fed with a 12 gram cartridge. So that will be our example.

We know that 1.8 grams of CO2 == 61.02in3 so (12/1.8)(61.02)=406.7Vin3 at 1atm

We know that 1atm == 14.7 PSI so (406.7) * 14.7 / 150 = 39.86in3

So 12 grams of CO2 will fill 39.86in3 at 150 PSI at 77F.

This is safe because we are well below the critical temperature and pressures.

Having safety checked we can now find how much of what sized pipe will give us that volume.

## Pressure of CO2 at a given volume for a given amount

This is commonly asked as "if I dump a 12 gram into this chamber ,what is the pressure?" We have to watch this as if the pressure shows liquid state in the phase chart for that temperature then we do not have gaseous CO2 (which may or may not be a problem).

Let's assume a 1.5" PVC chamber 12" long. So it's volume V = ( pi *(1.592/2)**2 ) * 12 == 23.87 in3

We know that 1.8 grams of CO2 == 61.02 in3 at 1atm so

(12/1.8)*(61.02/23.87)*(14.7) = 250 PSI.

This is safe from a CO2 perspective because we are well below the critical temperature and pressures. This is borderline (to me dangerous) from a PVC application perspective.

If we wanted to lower the pressure to 150 PSI (my target maximum) with the same diameter pipe we'd have

250 / 150 * 12 == 20"

If we wanted to lower the pressure to 150 PSI with the same length pipe. Again, we scale the volume.

250/150 * (23.87/12) = 3.32in2 where 3.32in2 = pi (r**2) so r = 1.028 so d = 2.056 inches

We see that 2.056 inches is very close to the 2.049 inch ID of 2" PVC so we are done. If the computation had yielded a diameter that was not close to a standard pipe sise then we would need to go either up or down a size and accept either a different chamber length, a different working pressure, or both (always double checking for safety).

DoomLabs PVC & Copper Pipe Specifications Page

A google search for CO2, pressure, and atmosphere

http://newton.dep.anl.gov/askasci/chem00/chem00306.htm for some CO2 discussions.

http://www.convert-me.com/en/ http://xtronics.com/reference/convert.htm and for units conversions

WarPig for Paintball Gases page. This has CO2 Phase chart and CO2 Dynamics page as well as other gas related information.

Pipeproperties of Steel &PVCsch 40, sch 80 & class 160